What is (2x+3)^2=5(-3y-2) ?

The solution to (2x+3)^2=5(-3y-2) is Parabola with (h,k)=(-3/2 ,-2/3),p=-15/16

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(2x+3)^2=5(-3y-2)

(2 x + 3)^{2} = 5 (- 3 y - 2)

(h, k) = (- \frac{3}{2}, - \frac{2}{3}), p = - \frac{15}{16}

Solution steps

(2 x + 3)^{2} = 5 (- 3 y - 2)

Rewrite

(2 x + 3)^{2} = 5 (- 3 y - 2)

in the standard form:

4 (- \frac{15}{16}) (y - (- \frac{2}{3})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{2}{3}), p = - \frac{15}{16}

(y - 1)^{2} = - 8 (x - 3)

(y - 1)^{2} = 10 (x - 2)

4 x^{2} + 8 y = 0

y^{2} - 4 y - 8 x + 28 = 0

y^{2} - 4 x - 6 y + 13 = 10

What is (2x+3)^2=5(-3y-2) ?
The solution to (2x+3)^2=5(-3y-2) is Parabola with (h,k)=(-3/2 ,-2/3),p=-15/16