What is ((y+1)^2)/9-((x-2)^2)/(16)=1 ?

The solution to ((y+1)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,-1),a=3,b=4

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((y+1)^2)/9-((x-2)^2)/(16)=1

\frac{( y + 1 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

(h, k) = (2, - 1), a = 3, b = 4

Solution steps

\frac{( y + 1 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( y + 1 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( x - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = 3, b = 4

\frac{x ^{2}}{9} - \frac{( y - 9 ) ^{2}}{16} = 1

4 x^{2} - 8 x - 3 y^{2} - 8 = 0

- 4 x^{2} + 9 y^{2} = - 9

(x - 0)^{2} - (y - 4)^{2} = 1

(x - 0)^{2} - (y - 4)^{2} = 2

What is ((y+1)^2)/9-((x-2)^2)/(16)=1 ?
The solution to ((y+1)^2)/9-((x-2)^2)/(16)=1 is Hyperbola with (h,k)=(2,-1),a=3,b=4