What is ((x+3)^2)/9-((y-1)^2)/(49)=1 ?

The solution to ((x+3)^2)/9-((y-1)^2)/(49)=1 is Hyperbola with (h,k)=(-3,1),a=3,b=7

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((x+3)^2)/9-((y-1)^2)/(49)=1

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{49} = 1

(h, k) = (- 3, 1), a = 3, b = 7

Solution steps

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{49} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, 1), a = 3, b = 7

9 y^{2} - z^{2} = 36

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{9} = 1

- 16 x^{2} + 4 y^{2} - 32 x + 16 y - 64 = 0

4 x^{2} - 16 x - 9 y^{2} = 20

\frac{17}{x + y} \frac{5}{x - y} = 5

What is ((x+3)^2)/9-((y-1)^2)/(49)=1 ?
The solution to ((x+3)^2)/9-((y-1)^2)/(49)=1 is Hyperbola with (h,k)=(-3,1),a=3,b=7