What is ((y-3)^2)/9-((x+1)^2)/(27)=1 ?

The solution to ((y-3)^2)/9-((x+1)^2)/(27)=1 is Hyperbola with (h,k)=(-1,3),a=3,b=3sqrt(3)

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((y-3)^2)/9-((x+1)^2)/(27)=1

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

(h, k) = (- 1, 3), a = 3, b = 33

Solution steps

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

Rewrite

\frac{( y - 3 ) ^{2}}{9} - \frac{( x + 1 ) ^{2}}{27} = 1

in the form of a standard hyperbola equation

\frac{( y - 3 ) ^{2}}{3 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{( 3 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 3), a = 3, b = 33

y^{2} - 4 x^{2} - 2 y + 24 x = 51

\frac{( x - 1 ) ^{2}}{36} - \frac{( y + 2 ) ^{2}}{25} = 1

\frac{x ^{2}}{3 0 ^{2}} - \frac{y ^{2}}{4 4 ^{2}} = 1

y^{2} - x^{2} = 8

y^{2} - x^{2} = 5

What is ((y-3)^2)/9-((x+1)^2)/(27)=1 ?
The solution to ((y-3)^2)/9-((x+1)^2)/(27)=1 is Hyperbola with (h,k)=(-1,3),a=3,b=3sqrt(3)