What is (x+2)^2-(y+2)^2=4^2 ?

The solution to (x+2)^2-(y+2)^2=4^2 is Hyperbola with (h,k)=(-2,-2),a=4,b=4

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(x+2)^2-(y+2)^2=4^2

(x + 2)^{2} - (y + 2)^{2} = 4^{2}

(h, k) = (- 2, - 2), a = 4, b = 4

Solution steps

(x + 2)^{2} - (y + 2)^{2} = 4^{2}

Rewrite

(x + 2)^{2} - (y + 2)^{2} = 4^{2}

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, - 2), a = 4, b = 4

4 x^{2} - 9 y^{2} - 11 = 0

4 x^{2} - \frac{1}{2} y^{2} + 8 x + 2 y - 2 = 0

\frac{3}{2} (v - \frac{3}{2})^{2} - \frac{1}{2} (u + \frac{3}{2})^{2} = 6

2 x^{2} - 5 y^{2} = 13

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{27} = 1

What is (x+2)^2-(y+2)^2=4^2 ?
The solution to (x+2)^2-(y+2)^2=4^2 is Hyperbola with (h,k)=(-2,-2),a=4,b=4