What is 2y^2-x^2=28 ?

The solution to 2y^2-x^2=28 is Hyperbola with (h,k)=(0,0),a=sqrt(14),b=2sqrt(7)

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2y^2-x^2=28

2 y^{2} - x^{2} = 28

(h, k) = (0, 0), a = 14, b = 27

Solution steps

2 y^{2} - x^{2} = 28

Rewrite

2 y^{2} - x^{2} = 28

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 14 ) ^{2}} - \frac{( x - 0 ) ^{2}}{( 2 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 14, b = 27

\frac{( x - 4 ) ^{2}}{9} - \frac{( Y ( x ) + 1 ) ^{2}}{4} = 1

\frac{( x - 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{9} = 1

x^{2} - y^{2} = y

4 x^{2} - 6 y^{2} = 24

9 x^{2} - 2 y^{2} = 18

What is 2y^2-x^2=28 ?
The solution to 2y^2-x^2=28 is Hyperbola with (h,k)=(0,0),a=sqrt(14),b=2sqrt(7)