What is 5X^2+4X-3(3Y-8)+6=-2(5X-5) ?

The solution to 5X^2+4X-3(3Y-8)+6=-2(5X-5) is Parabola with (h,k)=(-7/5 ,-23/15),p= 9/20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5X^2+4X-3(3Y-8)+6=-2(5X-5)

5 X^{2} + 4 X - 3 (3 Y - 8) + 6 = - 2 (5 X - 5)

(h, k) = (- \frac{7}{5}, - \frac{23}{15}), p = \frac{9}{20}

Solution steps

5 X^{2} + 4 X - 3 (3 Y - 8) + 6 = - 2 (5 X - 5)

Rewrite

5 X^{2} + 4 X - 3 (3 Y - 8) + 6 = - 2 (5 X - 5)

in the standard form

4 \cdot \frac{9}{20} (Y - (- \frac{23}{15})) = (X - (- \frac{7}{5}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{5}, - \frac{23}{15}), p = \frac{9}{20}

y > - 4 x^{2} - 12 x - 8

x + y^{2} - 3 = 0

x^{2} - 10 x - 2 y + 19 = 0

y^{2} - 8 x - 6 y + 25 = 0

y 2 y - 18 x = - 26

What is 5X^2+4X-3(3Y-8)+6=-2(5X-5) ?
The solution to 5X^2+4X-3(3Y-8)+6=-2(5X-5) is Parabola with (h,k)=(-7/5 ,-23/15),p= 9/20