What is ((y+2)^2)/(25)-((x-10)^2)/(36)=1 ?

The solution to ((y+2)^2)/(25)-((x-10)^2)/(36)=1 is Hyperbola with (h,k)=(10,-2),a=5,b=6

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((y+2)^2)/(25)-((x-10)^2)/(36)=1

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 10 ) ^{2}}{36} = 1

(h, k) = (10, - 2), a = 5, b = 6

Solution steps

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 10 ) ^{2}}{36} = 1

Rewrite

\frac{( y + 2 ) ^{2}}{25} - \frac{( x - 10 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{5 ^{2}} - \frac{( x - 10 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (10, - 2), a = 5, b = 6

\frac{( y - 3 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{9} = 1

2 x^{2} - 2 y = 2 y^{2} + 2 y + 2 x - 1

(\frac{x - 8}{3})^{2} - (\frac{y + 3}{4})^{2} = 1

\frac{y ^{2}}{20} - x^{2} = 1

9 x^{2} - 4 y^{2} - 36 x + 72 = 0

What is ((y+2)^2)/(25)-((x-10)^2)/(36)=1 ?
The solution to ((y+2)^2)/(25)-((x-10)^2)/(36)=1 is Hyperbola with (h,k)=(10,-2),a=5,b=6