What is (x^2)/8-(y^2)/8 =1 ?

The solution to (x^2)/8-(y^2)/8 =1 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(2)

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(x^2)/8-(y^2)/8 =1

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

(h, k) = (0, 0), a = 22, b = 22

Solution steps

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

Rewrite

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 2 2 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 22, b = 22

- 4 x^{2} + 9 y^{2} - 24 x - 54 y + 81 = 0

4 x^{(2)} - 9 y^{(2)} = 216

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{16} = 1

f (x) \cdot f (x) = 2 x^{2} - x - 10

\frac{y ^{2}}{100} - \frac{( x - 2 ) ^{2}}{64} = 1

What is (x^2)/8-(y^2)/8 =1 ?
The solution to (x^2)/8-(y^2)/8 =1 is Hyperbola with (h,k)=(0,0),a=2sqrt(2),b=2sqrt(2)