What is x^{(2)}-6=((y^{(2)}))/((3)) ?

The solution to x^{(2)}-6=((y^{(2)}))/((3)) is Hyperbola with (h,k)=(0,0),a=sqrt(6),b=3sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{(2)}-6=((y^{(2)}))/((3))

x^{(2)} - 6 = \frac{( y ^{(2)} )}{( 3 )}

(h, k) = (0, 0), a = 6, b = 32

Solution steps

x^{2} - 6 = \frac{y ^{2}}{3}

Rewrite

x^{2} - 6 = \frac{y ^{2}}{3}

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 6 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 3 2 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 32

\frac{x ^{2}}{9} + \frac{2 x}{3} - 9 y^{2} - 54 y - 81 = 0

\frac{1}{36} x^{2} - \frac{1}{4} y^{2} = 1

\frac{x ^{2}}{32} - \frac{y ^{2}}{25} = 1

yy = x^{2} - 9

4 x^{2} - y^{2} - 4 = 0

What is x^{(2)}-6=((y^{(2)}))/((3)) ?
The solution to x^{(2)}-6=((y^{(2)}))/((3)) is Hyperbola with (h,k)=(0,0),a=sqrt(6),b=3sqrt(2)