What is ((x-3)^2)/9-((y-1)^2)/4 =1 ?

The solution to ((x-3)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(3,1),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-3)^2)/9-((y-1)^2)/4 =1

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

(h, k) = (3, 1), a = 3, b = 2

Solution steps

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 1), a = 3, b = 2

\frac{( y - 4 ) ^{2}}{28} - \frac{( x + 1 ) ^{2}}{21} = 1

\frac{( y + 9 ) ^{2}}{92} - \frac{( x + 8 ) ^{2}}{36} = 17

\frac{x ^{2}}{6} - \frac{y ^{2}}{8} = 1

16 x^{2} - 96 x - 9 y^{2} - 18 y - 9 = 0

(r - 4)^{2} = (t + 4)^{2} + 32

What is ((x-3)^2)/9-((y-1)^2)/4 =1 ?
The solution to ((x-3)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(3,1),a=3,b=2