What is ((y+3)^2)/4-(x-1)^2=1 ?

The solution to ((y+3)^2)/4-(x-1)^2=1 is Hyperbola with (h,k)=(1,-3),a=2,b=1

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((y+3)^2)/4-(x-1)^2=1

\frac{( y + 3 ) ^{2}}{4} - (x - 1)^{2} = 1

(h, k) = (1, - 3), a = 2, b = 1

Solution steps

\frac{( y + 3 ) ^{2}}{4} - (x - 1)^{2} = 1

Rewrite

\frac{( y + 3 ) ^{2}}{4} - (x - 1)^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{2 ^{2}} - \frac{( x - 1 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 3), a = 2, b = 1

(\frac{x + 2}{10})^{2} - (\frac{y + 4}{25})^{2} = 1

4 (x + 1)^{2} - 3 (y - 2)^{2} = 15

4 x^{2} - 3 y^{2} + 8 x + 16 = 0

(x + 5)^{2} - (y + 6)^{2} = 20

- x^{2} + 2 y^{2} = 1

What is ((y+3)^2)/4-(x-1)^2=1 ?
The solution to ((y+3)^2)/4-(x-1)^2=1 is Hyperbola with (h,k)=(1,-3),a=2,b=1