What is ((y-7)^2)/(32)-((x-1)^2)/(64)=1 ?

The solution to ((y-7)^2)/(32)-((x-1)^2)/(64)=1 is Hyperbola with (h,k)=(1,7),a=4sqrt(2),b=8

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((y-7)^2)/(32)-((x-1)^2)/(64)=1

\frac{( y - 7 ) ^{2}}{32} - \frac{( x - 1 ) ^{2}}{64} = 1

(h, k) = (1, 7), a = 42, b = 8

Solution steps

\frac{( y - 7 ) ^{2}}{32} - \frac{( x - 1 ) ^{2}}{64} = 1

Rewrite

\frac{( y - 7 ) ^{2}}{32} - \frac{( x - 1 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( y - 7 ) ^{2}}{( 4 2 ) ^{2}} - \frac{( x - 1 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 7), a = 42, b = 8

36 x^{2} - 16 y^{2} - 144 x + 128 y - 265 = 0

16 x^{2} - y^{2} = 1

9 x^{2} - 16 y^{2} - 54 x - 64 y - 127 = 0

4 x^{2} - 5 y^{2} = 7

\frac{1}{x ^{2} - y ^{2}} \geq 1

What is ((y-7)^2)/(32)-((x-1)^2)/(64)=1 ?
The solution to ((y-7)^2)/(32)-((x-1)^2)/(64)=1 is Hyperbola with (h,k)=(1,7),a=4sqrt(2),b=8