What is ((x-6)^2)/4-((y+6)^2)/(81)=1 ?

The solution to ((x-6)^2)/4-((y+6)^2)/(81)=1 is Hyperbola with (h,k)=(6,-6),a=2,b=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-6)^2)/4-((y+6)^2)/(81)=1

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

(h, k) = (6, - 6), a = 2, b = 9

Solution steps

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{4} - \frac{( y + 6 ) ^{2}}{81} = 1

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{9 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, - 6), a = 2, b = 9

x^{2} - y^{2} - 8 x - 4 y - 61 = 0

x^{2} - y^{2} + x - \frac{1}{2} y + 1 = 0

9 x^{2} - y^{2} + 72 x + 108 = 0

\frac{3 r ^{2}}{t + 2} \geq 5 t

36 x^{2} - 25 y^{2} = 900

What is ((x-6)^2)/4-((y+6)^2)/(81)=1 ?
The solution to ((x-6)^2)/4-((y+6)^2)/(81)=1 is Hyperbola with (h,k)=(6,-6),a=2,b=9