What is ((x+2)^2)/9-((y-1)^2)/4 =1 ?

The solution to ((x+2)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(-2,1),a=3,b=2

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((x+2)^2)/9-((y-1)^2)/4 =1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

(h, k) = (- 2, 1), a = 3, b = 2

Solution steps

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( y - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 3, b = 2

x^{2} = 2 y^{2} + 6

(2 x - 1)^{2} + (3 x - 1)^{2} = y^{2}

36 y^{2} - 5 x^{2} = 180

\frac{( x + 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{16} = 1

\frac{( x - 2 ) ^{2}}{7} - \frac{( y + 1 ) ^{2}}{9} = 1

What is ((x+2)^2)/9-((y-1)^2)/4 =1 ?
The solution to ((x+2)^2)/9-((y-1)^2)/4 =1 is Hyperbola with (h,k)=(-2,1),a=3,b=2