What is 4x^2-25y^2+48+150-181=0 ?

The solution to 4x^2-25y^2+48+150-181=0 is Hyperbola with (h,k)=(0,0),a=(sqrt(17))/5 ,b=(sqrt(17))/2

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4x^2-25y^2+48+150-181=0

4 x^{2} - 25 y^{2} + 48 + 150 - 181 = 0

(h, k) = (0, 0), a = \frac{17}{5}, b = \frac{17}{2}

Solution steps

4 x^{2} - 25 y^{2} + 48 + 150 - 181 = 0

Rewrite

4 x^{2} - 25 y^{2} + 48 + 150 - 181 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( \frac{17}{5} ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{17}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = \frac{17}{5}, b = \frac{17}{2}

9 y^{2} + 36 y - 4 x^{2} - 16 x - 16 = 0

\frac{x ^{2}}{56} - \frac{y ^{2}}{20} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( y - 4 ) ^{2}}{48} - \frac{( x + 1 ) ^{2}}{9} = 1

25 y^{(2)} - 16 x^{(2)} - 400 = 0

What is 4x^2-25y^2+48+150-181=0 ?
The solution to 4x^2-25y^2+48+150-181=0 is Hyperbola with (h,k)=(0,0),a=(sqrt(17))/5 ,b=(sqrt(17))/2