What is (x^2)/(1^2)-(z^2)/(2^2)=1 ?

The solution to (x^2)/(1^2)-(z^2)/(2^2)=1 is Hyperbola with (h,k)=(0,0),a=1,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(1^2)-(z^2)/(2^2)=1

\frac{x ^{2}}{1 ^{2}} - \frac{z ^{2}}{2 ^{2}} = 1

(h, k) = (0, 0), a = 1, b = 2

Solution steps

\frac{x ^{2}}{1 ^{2}} - \frac{z ^{2}}{2 ^{2}} = 1

Rewrite

\frac{x ^{2}}{1 ^{2}} - \frac{z ^{2}}{2 ^{2}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( z - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 2

x^{2} - 4 y^{2} + 2 x - 32 y - 67 = 0

\frac{x ^{2} - y ^{2}}{3} = 1

\frac{( y - 4 ) ^{2}}{100} - \frac{( x - 7 ) ^{2}}{49} = 1

- x^{2} + 9 y^{2} - 54 y + 45 = 0

9 x^{2} - 25 y^{2} - 90 x - 100 y - 100 = 0

What is (x^2)/(1^2)-(z^2)/(2^2)=1 ?
The solution to (x^2)/(1^2)-(z^2)/(2^2)=1 is Hyperbola with (h,k)=(0,0),a=1,b=2