What is ((x+4)^2)/(36)-((y-2)^2)/(16)=1 ?

The solution to ((x+4)^2)/(36)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-4,2),a=6,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x+4)^2)/(36)-((y-2)^2)/(16)=1

\frac{( x + 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

(h, k) = (- 4, 2), a = 6, b = 4

Solution steps

\frac{( x + 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 2), a = 6, b = 4

- 64 x^{2} + 25 y^{2} - 1152 x - 350 y - 5559 = 0

5 y^{(2)} - 16 x^{(2)} - 400 = 0

x^{2} - y^{2} + 7 x + 8 y - 5 = 0

\frac{( y - 1 ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

2 x^{2} - 4 y^{2} + 12 x + 8 y + 10 = 0

What is ((x+4)^2)/(36)-((y-2)^2)/(16)=1 ?
The solution to ((x+4)^2)/(36)-((y-2)^2)/(16)=1 is Hyperbola with (h,k)=(-4,2),a=6,b=4