What is ((x-1)^2)/(64)-((y-7)^2)/(64)=1 ?

The solution to ((x-1)^2)/(64)-((y-7)^2)/(64)=1 is Hyperbola with (h,k)=(1,7),a=8,b=8

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((x-1)^2)/(64)-((y-7)^2)/(64)=1

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 7 ) ^{2}}{64} = 1

(h, k) = (1, 7), a = 8, b = 8

Solution steps

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 7 ) ^{2}}{64} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{64} - \frac{( y - 7 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{8 ^{2}} - \frac{( y - 7 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 7), a = 8, b = 8

64 Y^{2} - 25 X^{2} = 1600

\frac{( y - 4 ) ^{2}}{25} - \frac{( x + 6 ) ^{2}}{9} = 1

x^{2} - 2 x - y^{2} = 1

- x^{2} + y^{2} = 16

- x^{2} + y^{2} = 12

What is ((x-1)^2)/(64)-((y-7)^2)/(64)=1 ?
The solution to ((x-1)^2)/(64)-((y-7)^2)/(64)=1 is Hyperbola with (h,k)=(1,7),a=8,b=8