What is ((y+8)^2)/(16)-((x+4)^2)/(25)=1 ?

The solution to ((y+8)^2)/(16)-((x+4)^2)/(25)=1 is Hyperbola with (h,k)=(-4,-8),a=4,b=5

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((y+8)^2)/(16)-((x+4)^2)/(25)=1

\frac{( y + 8 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

(h, k) = (- 4, - 8), a = 4, b = 5

Solution steps

\frac{( y + 8 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 8 ) ^{2}}{16} - \frac{( x + 4 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 8 ) ) ^{2}}{4 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 8), a = 4, b = 5

a^{2} - b^{2} = 3

a^{2} - b^{2} = 5

\frac{( y - 6 ) ^{2}}{49} - \frac{( x + 2 ) ^{2}}{64} = 1

9 y^{2} - 4 x^{2} - 18 y + 24 x - 63 = 0

2 x^{2} - 4 y^{2} = 4^{2}

What is ((y+8)^2)/(16)-((x+4)^2)/(25)=1 ?
The solution to ((y+8)^2)/(16)-((x+4)^2)/(25)=1 is Hyperbola with (h,k)=(-4,-8),a=4,b=5