What is (5x-4)^2=(8y+2)*y ?

The solution to (5x-4)^2=(8y+2)*y is Hyperbola with (h,k)=(4/5 ,-1/8),a= 1/8 ,b= 1/(10sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(5x-4)^2=(8y+2)*y

(5 x - 4)^{2} = (8 y + 2) \cdot y

(h, k) = (\frac{4}{5}, - \frac{1}{8}), a = \frac{1}{8}, b = \frac{1}{10 2}

Solution steps

(5 x - 4)^{2} = (8 y + 2) y

Rewrite

(5 x - 4)^{2} - (8 y + 2) y = 0

in the form of a standard hyperbola equation

\frac{( y - ( - \frac{1}{8} ) ) ^{2}}{( \frac{1}{8} ) ^{2}} - \frac{( x - \frac{4}{5} ) ^{2}}{( \frac{1}{10 2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (\frac{4}{5}, - \frac{1}{8}), a = \frac{1}{8}, b = \frac{1}{10 2}

4 x^{2} - 8 y^{2} \leq 12

\frac{( x - 3 ) ^{2}}{25} - \frac{( y + 2 ) ^{2}}{9} = 1

x^{2} - y^{2} - 8 x - 8 y - 15 = 0

\frac{a + 10}{b} = \frac{b}{a}

(x - 2)^{2} - (y + 5)^{2} = 18

What is (5x-4)^2=(8y+2)*y ?
The solution to (5x-4)^2=(8y+2)*y is Hyperbola with (h,k)=(4/5 ,-1/8),a= 1/8 ,b= 1/(10sqrt(2))