What is ((x-2)^2)/4-((y+3)^2)/1 =1 ?

The solution to ((x-2)^2)/4-((y+3)^2)/1 =1 is Hyperbola with (h,k)=(2,-3),a=2,b=1

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((x-2)^2)/4-((y+3)^2)/1 =1

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{1} = 1

(h, k) = (2, - 3), a = 2, b = 1

Solution steps

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{1} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{1} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 3 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 3), a = 2, b = 1

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

x^{2} - 4 y^{2} + 2 x + 16 y - 11 = 0

2 x^{2} - 3 y^{2} = 1

9 x^{2} - 4 y^{2} + 36 x - 16 y - 16 = 0

y^{2} = - 0.8944 + 1.125 x^{2}

What is ((x-2)^2)/4-((y+3)^2)/1 =1 ?
The solution to ((x-2)^2)/4-((y+3)^2)/1 =1 is Hyperbola with (h,k)=(2,-3),a=2,b=1