What is (y^2-((x+1)^2))/4 =1 ?

The solution to (y^2-((x+1)^2))/4 =1 is Hyperbola with (h,k)=(-1,0),a=2,b=2

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(y^2-((x+1)^2))/4 =1

\frac{y ^{2} - ( ( x + 1 ) ^{2} )}{4} = 1

(h, k) = (- 1, 0), a = 2, b = 2

Solution steps

\frac{y ^{2} - ( x + 1 ) ^{2}}{4} = 1

Rewrite

\frac{y ^{2} - ( x + 1 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 0), a = 2, b = 2

x^{2} - 4 y^{2} - 2 x + 16 y - 31 = 0

x^{2} - 64 y^{2} = 64

\frac{36 ( x - 7 ) ^{2} - 64 ( y - 6 ) ^{2}}{2304} = 1

(y - 4)^{2} = \frac{4 ( x + 1 ) ^{2} + 84}{3}

3 (x + \frac{1}{3})^{2} - 3 (y - \frac{7}{3})^{2} = - 40

What is (y^2-((x+1)^2))/4 =1 ?
The solution to (y^2-((x+1)^2))/4 =1 is Hyperbola with (h,k)=(-1,0),a=2,b=2