5x^2+18y-180=0

Lösung

5 x^{2} + 18 y - 180 = 0

(h, k) = (0, 10), p = - \frac{9}{10}

Schritte zur Lösung

5 x^{2} + 18 y - 180 = 0

Rewrite

5 x^{2} + 18 y - 180 = 0

in the standard form:

4 (- \frac{9}{10}) (y - 10) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 10), p = - \frac{9}{10}

x^{2} + (y - 1) 2 = 9

2 x^{2} - 4 y + 6 = 0

y^{2} - 6 y - 36 x + 117 = 0

\frac{2}{x} = \frac{x}{y}

x^{2} - 6 x - 7 y = 12