-((x-3)^2)/(25)+((y-4)^2)/(36)=1

解答

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

(h, k) = (3, 4), a = 6, b = 5

求解步骤

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

将

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{36} = 1

改写为标准双曲线方程形式

\frac{( y - 4 ) ^{2}}{6 ^{2}} - \frac{( x - 3 ) ^{2}}{5 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (3, 4), a = 6, b = 5

137 + 6 y = y^{2} - 24 x - x^{2}

\frac{y ^{2}}{25} - \frac{( x - 5 ) ^{2}}{16} = 1

4 x^{2} - y^{2} - 12 y + 36 = 0

9 x^{2} - 72 x - 4 y^{2} - 40 y + 44 = 36

4 x^{2} + 24 x - 2 y^{2} + 36 = 36