x^2+3x-2y^2+y-23=0

解

x^{2} + 3 x - 2 y^{2} + y - 23 = 0

(h, k) = (- \frac{3}{2}, \frac{1}{4}), a = \frac{201}{2 2}, b = \frac{201}{4}

解答ステップ

x^{2} + 3 x - 2 y^{2} + y - 23 = 0

x^{2} + 3 x - 2 y^{2} + y - 23 = 0

を標準的な双曲線のequationで書き換える

\frac{( x - ( - \frac{3}{2} ) ) ^{2}}{( \frac{201}{2 2} ) ^{2}} - \frac{( y - \frac{1}{4} ) ^{2}}{( \frac{201}{4} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (- \frac{3}{2}, \frac{1}{4}), a = \frac{201}{2 2}, b = \frac{201}{4}