What is 9x^2-16y^2-108x+64y+116=0 ?

The solution to 9x^2-16y^2-108x+64y+116=0 is Hyperbola with (h,k)=(6,2),a=4,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9x^2-16y^2-108x+64y+116=0

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

(h, k) = (6, 2), a = 4, b = 3

Solution steps

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

Rewrite

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, 2), a = 4, b = 3

\frac{( y + 3 ) ^{2}}{2} - \frac{( x - 1 ) ^{2}}{18} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{16} = 1

x^{2} - 3 y^{2} + 11 x + y + 10 = 0

16 y^{2} - 4 x^{2} - 24 x - 12 y - 34 = 0

x^{2} + x - y^{2} = 5

What is 9x^2-16y^2-108x+64y+116=0 ?
The solution to 9x^2-16y^2-108x+64y+116=0 is Hyperbola with (h,k)=(6,2),a=4,b=3