What is 7x^2-5y^2-14x+40y-108=0 ?

The solution to 7x^2-5y^2-14x+40y-108=0 is Hyperbola with (h,k)=(1,4),a=sqrt(5),b=sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7x^2-5y^2-14x+40y-108=0

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

(h, k) = (1, 4), a = 5, b = 7

Solution steps

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

Rewrite

7 x^{2} - 5 y^{2} - 14 x + 40 y - 108 = 0

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 4 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 4), a = 5, b = 7

y^{2} - x^{2} = 25

36 (x - 5)^{2} - 64 (y - 2)^{2} = 2304

\frac{( y - 4 ) ^{2}}{36} - \frac{( x - 1 ) ^{2}}{16} = 1

- 16 x^{2} + y^{2} + 128 x + 2 y - 271 = 0

x^{2} - 36 y^{2} = 36

What is 7x^2-5y^2-14x+40y-108=0 ?
The solution to 7x^2-5y^2-14x+40y-108=0 is Hyperbola with (h,k)=(1,4),a=sqrt(5),b=sqrt(7)