What is ((x-2)^2)/(36)-((y+1)^2)/(64)=1 ?

The solution to ((x-2)^2)/(36)-((y+1)^2)/(64)=1 is Hyperbola with (h,k)=(2,-1),a=6,b=8

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((x-2)^2)/(36)-((y+1)^2)/(64)=1

\frac{( x - 2 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

(h, k) = (2, - 1), a = 6, b = 8

Solution steps

\frac{( x - 2 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 2 ) ^{2}}{6 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, - 1), a = 6, b = 8

- x^{2} + y^{2} = - 13

- x^{2} + y^{2} = 51

y^{2} + 3 = x^{2}

\frac{( y + 1 ) ^{2}}{16} - \frac{( x - 2 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{16} = 1

What is ((x-2)^2)/(36)-((y+1)^2)/(64)=1 ?
The solution to ((x-2)^2)/(36)-((y+1)^2)/(64)=1 is Hyperbola with (h,k)=(2,-1),a=6,b=8