What is ((y-5)^2)/(15)-((x+4)^2)/(49)=1 ?

The solution to ((y-5)^2)/(15)-((x+4)^2)/(49)=1 is Hyperbola with (h,k)=(-4,5),a=sqrt(15),b=7

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((y-5)^2)/(15)-((x+4)^2)/(49)=1

\frac{( y - 5 ) ^{2}}{15} - \frac{( x + 4 ) ^{2}}{49} = 1

(h, k) = (- 4, 5), a = 15, b = 7

Solution steps

\frac{( y - 5 ) ^{2}}{15} - \frac{( x + 4 ) ^{2}}{49} = 1

Rewrite

\frac{( y - 5 ) ^{2}}{15} - \frac{( x + 4 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( y - 5 ) ^{2}}{( 15 ) ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 5), a = 15, b = 7

y^{2} - 4 x^{2} - 24 x - 32 = 0

4 x^{2} - 9 y^{2} + 8 x + 36 y - 68 = 0

y^{2} + 2 = x^{2} - 2

3 x^{2} - 12 x - \frac{y ^{2}}{4} - \frac{y}{2} + \frac{43}{4} = 0

- x^{2} + 3 y^{2} - 4 x + 6 y = 28

What is ((y-5)^2)/(15)-((x+4)^2)/(49)=1 ?
The solution to ((y-5)^2)/(15)-((x+4)^2)/(49)=1 is Hyperbola with (h,k)=(-4,5),a=sqrt(15),b=7