What is (y^2)/2-(x^2)/(8/7)=1 ?

The solution to (y^2)/2-(x^2)/(8/7)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=(2sqrt(2))/(sqrt(7))

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(y^2)/2-(x^2)/(8/7)=1

\frac{y ^{2}}{2} - \frac{x ^{2}}{\frac{8}{7}} = 1

(h, k) = (0, 0), a = 2, b = \frac{2 2}{7}

Solution steps

\frac{y ^{2}}{2} - \frac{x ^{2}}{\frac{8}{7}} = 1

Rewrite

\frac{y ^{2}}{2} - \frac{x ^{2}}{\frac{8}{7}} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} - \frac{( x - 0 ) ^{2}}{( \frac{2 2}{7} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = \frac{2 2}{7}

4 x^{2} - y^{2} - 4 x + 3 y - 26 = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{4} = 1

- 9 x^{2} + 4 y^{2} - 144 = 0

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

(x - 2)^{2} = 4 y (y + 2)

What is (y^2)/2-(x^2)/(8/7)=1 ?
The solution to (y^2)/2-(x^2)/(8/7)=1 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=(2sqrt(2))/(sqrt(7))