What is 4x^2-9y^2+36=0 ?

The solution to 4x^2-9y^2+36=0 is Hyperbola with (h,k)=(0,0),a=2,b=3

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4x^2-9y^2+36=0

4 x^{2} - 9 y^{2} + 36 = 0

(h, k) = (0, 0), a = 2, b = 3

Solution steps

4 x^{2} - 9 y^{2} + 36 = 0

Rewrite

4 x^{2} - 9 y^{2} + 36 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{2 ^{2}} - \frac{( x - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 3

8 x^{2} - 3 y^{2} = 120

5 y^{2} - 16 x^{2} + 400 = 0

9 x^{2} - 4 y^{2} + 54 x + 8 y + 41 = 0

\frac{( x - 3 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

2 x^{2} - 2 y^{2} + 3 x - 2 y - 43 = 0

What is 4x^2-9y^2+36=0 ?
The solution to 4x^2-9y^2+36=0 is Hyperbola with (h,k)=(0,0),a=2,b=3