What is ((x-1)^2}{16}-\frac{(y+2)^2)/9 =1 ?

The solution to ((x-1)^2}{16}-\frac{(y+2)^2)/9 =1 is Hyperbola with (h,k)=(1,-2),a=4,b=3

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((x-1)^2}{16}-\frac{(y+2)^2)/9 =1

\frac{( x - 1 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{9} = 1

(h, k) = (1, - 2), a = 4, b = 3

Solution steps

\frac{( x - 1 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{16} - \frac{( y + 2 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{4 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 4, b = 3

9 x^{2} - 9 y^{2} = 81

x^{2} - y^{2} = 64

x^{2} - y^{2} = 65

- x^{2} + y^{2} = 4

- x^{2} + y^{2} = 9

What is ((x-1)^2}{16}-\frac{(y+2)^2)/9 =1 ?
The solution to ((x-1)^2}{16}-\frac{(y+2)^2)/9 =1 is Hyperbola with (h,k)=(1,-2),a=4,b=3