What is (x^2)/4-(y^2)/(36)=1 ?

The solution to (x^2)/4-(y^2)/(36)=1 is Hyperbola with (h,k)=(0,0),a=2,b=6

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(x^2)/4-(y^2)/(36)=1

\frac{x ^{2}}{4} - \frac{y ^{2}}{36} = 1

(h, k) = (0, 0), a = 2, b = 6

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 6

x^{2} + 2 y + x = 2 y^{2} + 3 y + 2 x + 2

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

(x + y) (x - y) - 2 = 0

\frac{y ^{2}}{a ^{2}} - \frac{x ^{2}}{b ^{2}} = 1

\frac{( y - 5 ) ^{2}}{25} - \frac{( x + 5 ) ^{2}}{9} = 1

What is (x^2)/4-(y^2)/(36)=1 ?
The solution to (x^2)/4-(y^2)/(36)=1 is Hyperbola with (h,k)=(0,0),a=2,b=6