What is ((x-1)^2)/(36)-((y-2)^2)/(64)=1 ?

The solution to ((x-1)^2)/(36)-((y-2)^2)/(64)=1 is Hyperbola with (h,k)=(1,2),a=6,b=8

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((x-1)^2)/(36)-((y-2)^2)/(64)=1

\frac{( x - 1 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

(h, k) = (1, 2), a = 6, b = 8

Solution steps

\frac{( x - 1 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{6 ^{2}} - \frac{( y - 2 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 6, b = 8

\frac{( x + 1 ) ^{2}}{3} - \frac{( y - 1 ) ^{2}}{5} = 1

- 36 x^{2} + y^{2} = 36

16 x^{2} - 9 y^{2} + 96 x + 36 y + 252 = 0

4 y^{2} - x^{2} = 36

4 x^{2} - 9 y^{2} - 16 x + 18 y - 11 = 0

What is ((x-1)^2)/(36)-((y-2)^2)/(64)=1 ?
The solution to ((x-1)^2)/(36)-((y-2)^2)/(64)=1 is Hyperbola with (h,k)=(1,2),a=6,b=8