What is ((x+5)^2)/(16)-((y-2)^2)/(36)=1 ?

The solution to ((x+5)^2)/(16)-((y-2)^2)/(36)=1 is Hyperbola with (h,k)=(-5,2),a=4,b=6

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((x+5)^2)/(16)-((y-2)^2)/(36)=1

\frac{( x + 5 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{36} = 1

(h, k) = (- 5, 2), a = 4, b = 6

Solution steps

\frac{( x + 5 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 5 ) ^{2}}{16} - \frac{( y - 2 ) ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 5 ) ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, 2), a = 4, b = 6

y^{2} = x^{2} + 144

\frac{x ^{2}}{4} - \frac{3 y ^{2}}{4} = 1

y^{2} - 4 x^{2} = 12

3 x^{2} - y^{2} \leq 9

4 y^{2} - 49 x^{2} - 392 x + 16 y - 964 = 0

What is ((x+5)^2)/(16)-((y-2)^2)/(36)=1 ?
The solution to ((x+5)^2)/(16)-((y-2)^2)/(36)=1 is Hyperbola with (h,k)=(-5,2),a=4,b=6