What is (x^2)/4-((y-6)^2)/(140)=1 ?

The solution to (x^2)/4-((y-6)^2)/(140)=1 is Hyperbola with (h,k)=(0,6),a=2,b=2sqrt(35)

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(x^2)/4-((y-6)^2)/(140)=1

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

(h, k) = (0, 6), a = 2, b = 235

Solution steps

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 6 ) ^{2}}{( 2 35 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 6), a = 2, b = 235

What is (x^2)/4-((y-6)^2)/(140)=1 ?
The solution to (x^2)/4-((y-6)^2)/(140)=1 is Hyperbola with (h,k)=(0,6),a=2,b=2sqrt(35)