What is ((x-1)^2)/4-((y+2)^2)/9 =-1 ?

The solution to ((x-1)^2)/4-((y+2)^2)/9 =-1 is Hyperbola with (h,k)=(1,-2),a=3,b=2

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((x-1)^2)/4-((y+2)^2)/9 =-1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = - 1

(h, k) = (1, - 2), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = - 1

Rewrite

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = - 1

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 2), a = 3, b = 2

(y - 1)^{2} - x^{2} + 1 = 50

y^{2} = x^{2} + 2

117 x^{2} - 52 y^{2} + 702 x - 208 y + 1169 = 0

\frac{( y - 3 ) ^{2}}{9} - x^{2} = 1

4 x^{2} - y^{2} + 8 x + 4 y = 15

What is ((x-1)^2)/4-((y+2)^2)/9 =-1 ?
The solution to ((x-1)^2)/4-((y+2)^2)/9 =-1 is Hyperbola with (h,k)=(1,-2),a=3,b=2