What is 5x^2-4y^2+80=0 ?

The solution to 5x^2-4y^2+80=0 is Hyperbola with (h,k)=(0,0),a=2sqrt(5),b=4

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5x^2-4y^2+80=0

5 x^{2} - 4 y^{2} + 80 = 0

(h, k) = (0, 0), a = 25, b = 4

Solution steps

5 x^{2} - 4 y^{2} + 80 = 0

Rewrite

5 x^{2} - 4 y^{2} + 80 = 0

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{( 2 5 ) ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 25, b = 4

3 x^{2} - 2 y^{2} + 6 x + 4 = 0

16 y^{2} - x^{2} + 2 x + 64 y - 1 = 0

\frac{x ^{2}}{16 + ( y - 4 ) ^{2}} = 1

- \frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

16 x^{2} - 9 y^{2} - 64 x + 54 y - 161 = 0

What is 5x^2-4y^2+80=0 ?
The solution to 5x^2-4y^2+80=0 is Hyperbola with (h,k)=(0,0),a=2sqrt(5),b=4