What is ((x-6)^2}{16}-\frac{(y-4)^2)/9 =1 ?

The solution to ((x-6)^2}{16}-\frac{(y-4)^2)/9 =1 is Hyperbola with (h,k)=(6,4),a=4,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-6)^2}{16}-\frac{(y-4)^2)/9 =1

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

(h, k) = (6, 4), a = 4, b = 3

Solution steps

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 6 ) ^{2}}{16} - \frac{( y - 4 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - 6 ) ^{2}}{4 ^{2}} - \frac{( y - 4 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (6, 4), a = 4, b = 3

x^{2} - 3 y^{2} + 5 y = 7

3 x^{2} - 5 y^{2} + y = 2

x^{2} - 2 y^{2} = 8

25 y^{2} + 250 y - 16 x^{2} - 32 x + 209 = 0

x^{2} - 2 y^{2} - 4 x - 4 y - 400 = 0

What is ((x-6)^2}{16}-\frac{(y-4)^2)/9 =1 ?
The solution to ((x-6)^2}{16}-\frac{(y-4)^2)/9 =1 is Hyperbola with (h,k)=(6,4),a=4,b=3