What is 4x^2-4y^2-16=0 ?

The solution to 4x^2-4y^2-16=0 is Hyperbola with (h,k)=(0,0),a=2,b=2

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4x^2-4y^2-16=0

4 x^{2} - 4 y^{2} - 16 = 0

(h, k) = (0, 0), a = 2, b = 2

Solution steps

4 x^{2} - 4 y^{2} - 16 = 0

Rewrite

4 x^{2} - 4 y^{2} - 16 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 2

\frac{x ^{2}}{25} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{16} - \frac{y ^{2}}{16} = 1

4 x^{2} - y^{2} - 16 = 0

16 x^{2} - 25 y^{2} - 32 x + 100 y - 484 = 0

x, h (x)^{2} = x^{2} + 5 x

What is 4x^2-4y^2-16=0 ?
The solution to 4x^2-4y^2-16=0 is Hyperbola with (h,k)=(0,0),a=2,b=2