What is (y-2)^2-4(x+2)^2=4 ?

The solution to (y-2)^2-4(x+2)^2=4 is Hyperbola with (h,k)=(-2,2),a=2,b=1

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(y-2)^2-4(x+2)^2=4

(y - 2)^{2} - 4 (x + 2)^{2} = 4

(h, k) = (- 2, 2), a = 2, b = 1

Solution steps

(y - 2)^{2} - 4 (x + 2)^{2} = 4

Rewrite

(y - 2)^{2} - 4 (x + 2)^{2} = 4

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 2), a = 2, b = 1

x^{2} + y = x + y^{2} + 2018

\frac{( x - 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{5} = 1

\frac{( x - 4 ) ^{2}}{36} - \frac{( y + 3 ) ^{2}}{25} = 1

x^{2} - y^{2} = 36

What is (y-2)^2-4(x+2)^2=4 ?
The solution to (y-2)^2-4(x+2)^2=4 is Hyperbola with (h,k)=(-2,2),a=2,b=1