What is x^2-y^2+6x-4y-4=0 ?

The solution to x^2-y^2+6x-4y-4=0 is Hyperbola with (h,k)=(-3,-2),a=3,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-y^2+6x-4y-4=0

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

(h, k) = (- 3, - 2), a = 3, b = 3

Solution steps

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

Rewrite

x^{2} - y^{2} + 6 x - 4 y - 4 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 3 ) ) ^{2}}{3 ^{2}} - \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 3, - 2), a = 3, b = 3

\frac{y ^{2}}{16} - \frac{x ^{2}}{36} = 1

16 x^{2} - 9 y^{2} - 96 x + 288 = 0

\frac{( x + 4 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{4} = 1

24 x^{2} - 9 y^{2} = 216

4 x^{2} - 6 y^{2} = 9

What is x^2-y^2+6x-4y-4=0 ?
The solution to x^2-y^2+6x-4y-4=0 is Hyperbola with (h,k)=(-3,-2),a=3,b=3