What is ((x-5)^2)/4-((y+1)^2)/(49)=1 ?

The solution to ((x-5)^2)/4-((y+1)^2)/(49)=1 is Hyperbola with (h,k)=(5,-1),a=2,b=7

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((x-5)^2)/4-((y+1)^2)/(49)=1

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{49} = 1

(h, k) = (5, - 1), a = 2, b = 7

Solution steps

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{49} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{2 ^{2}} - \frac{( y - ( - 1 ) ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, - 1), a = 2, b = 7

4 (y - 3)^{2} - 9 (x - 2)^{2} = 36

\frac{x ^{2}}{25} - \frac{y ^{2}}{144} = 1

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

x^{2} - 4 y^{2} + 8 y - 8 = 0

\frac{x ^{2}}{16} - \frac{( y + 4 ) ^{2}}{81} = 1

What is ((x-5)^2)/4-((y+1)^2)/(49)=1 ?
The solution to ((x-5)^2)/4-((y+1)^2)/(49)=1 is Hyperbola with (h,k)=(5,-1),a=2,b=7