What is y^2-4x^2=16 ?

The solution to y^2-4x^2=16 is Hyperbola with (h,k)=(0,0),a=4,b=2

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y^2-4x^2=16

y^{2} - 4 x^{2} = 16

(h, k) = (0, 0), a = 4, b = 2

Solution steps

y^{2} - 4 x^{2} = 16

Rewrite

y^{2} - 4 x^{2} = 16

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

x^{2} - 4 y^{2} + 2 x + 8 y - 7 = 0

\frac{( x ^{(2)} )}{( 16 ) + ( y - 4 ) ^{(2)}} = 1

- 9 x^{2} + 25 y^{2} - 100 y - 125 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{11} = 1

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

What is y^2-4x^2=16 ?
The solution to y^2-4x^2=16 is Hyperbola with (h,k)=(0,0),a=4,b=2