What is x^2-4y^2-4>= 0 ?

The solution to x^2-4y^2-4>= 0 is Hyperbola with (h,k)=(0,0),a=2,b=1

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x^2-4y^2-4>= 0

x^{2} - 4 y^{2} - 4 \geq 0

(h, k) = (0, 0), a = 2, b = 1

Solution steps

x^{2} - 4 y^{2} - 4 \geq 0

Rewrite

x^{2} - 4 y^{2} - 4 \geq 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 1

9 x^{2} - 4 y^{2} - 72 x + 8 y + 176 = 0

\frac{( y - k ) ^{2}}{a ^{2}} - \frac{( x - h ) ^{2}}{b ^{2}} = 1

x, (x - 2)^{2} + (x - 3)^{2} = r (x)^{2}

x^{2} - y^{2} + 2 = 0

4 x^{2} - y^{2} = 4

What is x^2-4y^2-4>= 0 ?
The solution to x^2-4y^2-4>= 0 is Hyperbola with (h,k)=(0,0),a=2,b=1