What is (x^2)/4-(y^2)/(12)=1 ?

The solution to (x^2)/4-(y^2)/(12)=1 is Hyperbola with (h,k)=(0,0),a=2,b=2sqrt(3)

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(x^2)/4-(y^2)/(12)=1

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

(h, k) = (0, 0), a = 2, b = 23

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 23

x^{2} + 2 x - y^{2} + 1 - 4 = 0

8 x^{2} - 4 y^{2} + 10 x - 6 y - 8 = 0

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

\frac{( x - 5 ) ^{2}}{16} - \frac{( y + 7 ) ^{2}}{9} = - 1

2 x^{2} - y^{2} - 1 = 0

What is (x^2)/4-(y^2)/(12)=1 ?
The solution to (x^2)/4-(y^2)/(12)=1 is Hyperbola with (h,k)=(0,0),a=2,b=2sqrt(3)