What is the axis x^2+((y-6)^2)/(16)=1 ?

The axis x^2+((y-6)^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=1

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axis x^2+((y-6)^2)/(16)=1

axis

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

semi - major axis b = 4, semi - minor axis a = 1

Solution steps

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

Rewrite

x^{2} + \frac{( y - 6 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 6 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 6), a = 1, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 6), b = 4, a = 1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

(\frac{x - 3}{9})^{2} + (\frac{y + 1}{4})^{2} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

What is the axis x^2+((y-6)^2)/(16)=1 ?
The axis x^2+((y-6)^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=1