What is the axis (x+1)^2+1/4 y^2=1 ?

The axis (x+1)^2+1/4 y^2=1 is semi-major axis b=2, semi-minor axis a=1

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axis (x+1)^2+1/4 y^2=1

axis

(x + 1)^{2} + \frac{1}{4} y^{2} = 1

semi - major axis b = 2, semi - minor axis a = 1

Solution steps

(x + 1)^{2} + \frac{1}{4} y^{2} = 1

Rewrite

(x + 1)^{2} + \frac{1}{4} y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 0), b = 2, a = 1

3 x^{2} + 4 y^{2} + 27 x - 16 y + 48 = 0

\frac{( x - 4 ) ^{2}}{81} + \frac{( y + 9 ) ^{2}}{4} = 1

x^{2} + y^{2} + 10 x - 8 y = - 32

\frac{( x + 5 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{4} = 1

2 x^{2} + 3 y^{2} = 4

What is the axis (x+1)^2+1/4 y^2=1 ?
The axis (x+1)^2+1/4 y^2=1 is semi-major axis b=2, semi-minor axis a=1