What is the axis (x^2)/4+y^2=1 ?

The axis (x^2)/4+y^2=1 is semi-major axis a=2, semi-minor axis b=1

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axis (x^2)/4+y^2=1

axis

\frac{x ^{2}}{4} + y^{2} = 1

semi - major axis a = 2, semi - minor axis b = 1

Solution steps

\frac{x ^{2}}{4} + y^{2} = 1

Rewrite

\frac{x ^{2}}{4} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

x^{2} + 2 y^{2} + 2 x - 4 y - 1 = 0

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

4 x^{2} + 25 y^{2} + 32 x - 250 y + 589 = 0

4 x^{2} + y^{2} = 1

\frac{x ^{2}}{36} + \frac{y ^{2}}{100} = 1

What is the axis (x^2)/4+y^2=1 ?
The axis (x^2)/4+y^2=1 is semi-major axis a=2, semi-minor axis b=1